Suppose that $f(x) = 8 - 3x$. (a) Determine the average rate of change of $f$ between $x = 0$ and $x = 2$ and the average rate of change of $f$ between $x = 15$ and $x = 50$ (b) Were the two average rates of change that you found in part(a) the same? Explain why or why not.
Recall that the formula for averate rate is...
$\displaystyle \frac{f(b) - f(a)}{b - a}$
Thus,
$
\begin{equation}
\begin{aligned}
\text{a.) } \frac{f(2) - f(0)}{2 - 0} &= \frac{8-3(2) - [8-3(0)]}{2}\\
\\
&= \frac{8-6-8}{2}\\
\\
&= -3
\\
\\
\\
\frac{f(50) - f(15)}{50-15} &= \frac{8-3(50) - [ 8 - 3 (15) ] }{35}\\
\\
&= \frac{8-150-8+45}{35}\\
\\
&= \frac{-105}{35}\\
\\
&= -3
\end{aligned}
\end{equation}
$
b.) The average rates are the same in part(a). This shows that the distance covered between the two pair of points have equal slopes.
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