Evaluate the expression log3100−log318−log350
log3100−log318−log350=log3100−(log318+log350)log3100−log318−log350=log3100−log3(18⋅50)Law of Logarithms loga(AB)=logaA+logaBlog3100−log318−log350=log3(100900)Law of Logarithms loga(AB)=logaA−logaBlog3100−log318−log350=log3(19)Simplifylog3100−log318−log350=−2Because 3−2=19
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