Sunday, October 25, 2015

College Algebra, Chapter 1, 1.1, Section 1.1, Problem 32

The equation 1t1+t3t2=12 is either linear or equivalent to a linear equation. Solve the equation

1t1+t3t2=12Get the LCD of the left side3t2+t(t1)(t1)(3t2)=12Simplify3t2+t2t(t1)(3t2)=12Combine like termst2+2t2(t1)(3t2)=12Factor the numerator\cancel(t1)(t+2)\cancel(t1)(3t2)=12Cancel out like termst+23t2=12Multiply both sides by 2(3t2)2(\cancel3t2)[t+2\cancel3t2=1\cancel2]\cancel2(3t2)Simplify2(t+2)=3t2Apply Distributive property2t+4=3t2Combine like terms2t3t=42Simplifyt=6Multiply both sides by -11[t=6]1Simplifyt=6

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