Sunday, July 26, 2015

College Algebra, Chapter 1, 1.3, Section 1.3, Problem 48

Find all real solutions of 6x2+2x32=0.


6x2+2x32=0Given6x2+2x=32Add 32x2+26x=326Divide both sides of the equation by 6 to make the coefficient of x2 equal to 1x2+26+16=326+16Complete the square: add (262)2=16(x+16)2=23Perfect square, simplify the right side of the equationx+16=±23Take the square rootx=16±23Subtract 16x=16+23 and x=1623Solve for xx=66 and x=62Simplify

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