Use a graphing calculuator to check the results of the function f(t)=t5+2t−2t4 and its derivative
f′(t)=5−200t3−160t4−32t5(5+2t)2
Based from the graph, we can see that the function has a positive slope or positive derivative when it is increasing.
On the other hand, the function has a negative slope or negative derivative when the function is decreasing.
Also, the function has a zero slope at the maximum point of the graph.
Moreover, the function is not differentiable at x=−2.5 because it has a vertical tangent at that point.
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