A toddler has woo ten blocks showing the letters $C, E, F, H, N,$ and $R$. Find the probability that the child arranges the letters in the indicated order.
a.) In the order $FRENCH$.
There is only one correct arrangement of the letters in the order $FRENCH$. In the probability is defined as favorable outcomes divided by total outcomes. There are $6! = 720$ total arrangements. So the probability is $\displaystyle \frac{1}{720}$
b.) In alphabetical order
There are two arrangement of the letters in alphabetical order. The one is in ascending order and the other is in descending order. The probability is defined as a favorable outcomes divided by total outcomes. There are $6! = 720$ total arrangement. So the probability is $\displaystyle \frac{2}{720} = \frac{1}{360}$
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