Friday, January 9, 2015

College Algebra, Chapter 10, 10.4, Section 10.4, Problem 14

Five independent trials of a binomial experiment with probability of success p=0.7 and probability of failure q=0.3 are performed. Find the probability of each event.

At most three failures

Recall that the formula for the binomial probability is given by

C(n,r)prqnr

If the event should have at most three failures, then it means that the event must have at least two successes. Thus, we have


P(At least two successes)=P(exactly 2 successes)+P(exactly 3 successes)+P(exactly 4 successes)+P(exactly 5 successes)=C(5,2)(0.7)2(0.3)52+C(5,3)(0.7)3(0.3)53+C(5,4)(0.7)4(0.3)54+C(5,5)(0.7)5(0.3)55=0.1323+0.3087+0.36015+0.16807=0.96922

No comments:

Post a Comment