Tuesday, December 9, 2014

Single Variable Calculus, Chapter 1, 1.1, Section 1.1, Problem 25

Evaluate the difference quotient f(x)f(a)xa for the function f(x)=1x


f(x)f(a)xa=1x1axa(Substitute f(x) and f(a) to the function f(x), then divide it by (xa) and get the LCD)=axax(xa)( Simplify the equation)=1\cancel(xa)ax\cancel(xa)( Factor -1 in the numerator, and then cancel out like terms)=1ax

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