Evaluate the expression 5−i3+4i in the form of a+bi.
=5−i3+4i=(5−i3+4i)(3−4i3−4i)Multiply by the complex conjugate of the denominator=(5−i)(3−4i)32−(4i)2Use FOIL method in the denominator=15−20i−3i+4i29−(16i2)Recall that i2=−1=15−20i−3i+4(−1)9−(16(−1))Simplify=11−23i25Group terms=1125−2325i
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