Intermediate Algebra, Chapter 4, 4.1, Section 4.1, Problem 16

Solve the system $\begin{equation} \begin{aligned} x - 4y =& -4 \\ 3x + y =& 1 \end{aligned} \end{equation}$ by graphing.

To graph these linear equation, we plot several points for each line.

$x - 4y = -4$

$\begin{array}{c|c} x & y \\ \hline \\ -4 & 0 \\ 0 & 1 \\ 4 & 2 \end{array}$

$3x + y = 1$

$\begin{array}{c|c} x & y \\ \hline \\ -1 & 4 \\ 0 & 1 \\ 1 & -2 \end{array}$







Based from the graph, the point of intersection is $(0,1)$.

Therefore, the solution to the system is $(0,1)$.