Thursday, February 13, 2014

Single Variable Calculus, Chapter 1, 1.3, Section 1.3, Problem 63

(a) If f and g are even functions. What can you say about f+g and fg?


Let f(x)=x2g(x)=x4f+g=x2+x4fg=x2(x4)fg=x6


Therefore, f+g and fg are even functions.

(b) Then what if f and g are both odd?


Let f(x)=x3g(x)=x5f+g=x3+x5fg=x3(x5)fg=x8


Therefore, f+g is an odd function while fg is even.

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