(a) If f and g are even functions. What can you say about f+g and fg?
Let f(x)=x2g(x)=x4f+g=x2+x4fg=x2(x4)fg=x6
Therefore, f+g and fg are even functions.
(b) Then what if f and g are both odd?
Let f(x)=x3g(x)=x5f+g=x3+x5fg=x3(x5)fg=x8
Therefore, f+g is an odd function while fg is even.
No comments:
Post a Comment