a.) Determine the polynomial with real coefficients of the smallest possible degree for which i and 1+i are zeros and in which the coefficient of the highest power is 1.
b.) Determine the polynomial with complex coefficients of the smallest possible degree for which i and 1+i are zeros and in which the coefficient of the highest power is 1.
a.) Recall that if the polynomial function P has real coefficients and if a+bi is a zero of P, then a−bi is also a zero of P.
In our case, the zeros of P are i,−i,1+i and 1−i. Thus, the required polynomial has the form
P(x)=a(x−i)(x+i)[x−(1+i)][x−(1−i)] Model
P(x)=a(x−i)(x+i)[(x−1)−i][(x−1)+i]Regroup=a(x2−i2)[(x−1)2−i2]Difference of squares=a(x2−i2)[x2−2x+1−i2]Expand=a(x2+1)[x2−2x+1+1]Recall that i2=−1=a(x2+1)(x2−2x+2)Add the constants=a[x4−2x3+2x2+x2−2x+2]Expand=a[x4−2x3+3x2−2x+2]If the coefficient of the highest power is 1, then a=1=x4−2x3+3x2−2x+2
b.) If i and 1+i are zeros, then the request polynomials has the form
P(x)=a(x−i)[x−(1+i)]Model=a(x−i)(x−1−i)Distribute the negative sign=a(x2−x−ix−ix+i−i2)Expand=a(x2−x−2ix+i−i2)Combine like terms=a(x2−(1+2i)x+i+1)Simplify, recall that i2=−1=x2−(1+2i)x+i+1If the coefficient of the highest power is 1, then a=1
No comments:
Post a Comment