If T(x)=1√1+√x find functions f,g, and h such that f∘g∘h=T.
T=f(g(h(x)))
The formula says that, first, take the square root and add 1. Then, take the square root and lastly the result is the divisor of 1. So we let
h(x)=1+√x,g(x)=√x and f(x)=1x
Then, by checking
f(g(h(x)))=f(g(1+√x))=f(√1+√x)=1√1+√x
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