We are given a+b+c=395, b+c+d=1001 and aAs stated, d can take on a range of values.
Subtract the two equations:
b+c+d=1001a+b+c =395-----------------a +d=606 or
d=606+a
This isn't the whole story as we also know that aAssuming that a,b,c,d are integers there is a clear upper bound on a: a<130. (If a=131, then b+c=264 ==> b=c=132 but b
Assuming a,b,c,d are integers then the value of d depends on a ; d=606+a where -272If a,b,c,d are natural numbers then d=606+a where 0---------------------------------------------------------------------------
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