Beginning Algebra With Applications, Chapter 5, 5.2, Section 5.2, Problem 104

Graph $x + 2y = 4$ by using $x$- and $y$-intercepts

$x$-intercept:


$\begin{equation} \begin{aligned} x + 2y =& 4 && \text{Given equation} \\ x + 2(0) =& 4 && \text{To find the $x$-intercept, let } y = 0 \\ x =& 4 && \end{aligned} \end{equation}$


The $x$-intercept is $(4,0)$

$y$-intercept:


$\begin{equation} \begin{aligned} x + 2y =& 4 && \text{Given equation} \\ 0 + 2y =& 4 && \text{To find the $y$-intercept, let } x=0 \\ 2y =& 4 && \text{Divide by } 2 \\ y =& 2 && \end{aligned} \end{equation}$



The $y$-intercept is $(0,2)$

Graph the ordered pairs $(4,0)$ and $(0,2)$. Draw a straight line through the points.