A quadratic function f(x)=1+x−√2x2.
a.) Find the maximum or minimum value of the quadratic function f, using a graphing device.
Based from the graph, the function has a maximum value of 1.2.
b.) Find the exact maximum or minimum value of f.
Using the quadratic equation ax2+bx+c with a=−√2 and b=1. Thus, the maximum or minimum value occurs at
x=−b2a=−12(−√2)=12√2
Since a<0, the function has a maximum value
f(12√2)=1+12√2−√2(12√2)2=8+√28=1.18
No comments:
Post a Comment