Tuesday, January 3, 2012

College Algebra, Chapter 5, 5.3, Section 5.3, Problem 34

Expand the expression log(a2b4c), using Laws of Logarithm


log(a2b4c)=loga2log(b4c)Law of Logarithm loga(AB)=logaAlogaBlog(a2b4c)=loga2(logb4+logc)Law of Logarithm loga(AB)=logaA+logaBlog(a2b4c)=2loga(4logb+12logC)Law of Logarithm loga(AC)=ClogaAlog(a2b4c)=2loga4logb12logcDistributive Property

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