Sunday, November 6, 2011

College Algebra, Chapter 5, 5.3, Section 5.3, Problem 52

Combine the expression 2(log5x+2log5y3log5z), using the Laws of Logarithm


2(log5x+2log5y3log5z)=2(log5x+log5y2log5z3)Law of Logarithm loga(AC)=ClogaA2(log5x+2log5y3log5z)=2(log5xy2log5z3)Law of Logarithm loga(AB)=logaA+logaB2(log5x+2log5y3log5z)=2log5(xy2z3)Law of Logarithm loga(AB)=logaAlogaB2(log5x+2log5y3log5z)=log5(xy2z3)2Law of Logarithm loga(AC)=ClogaA

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