Combine the expression 2(log5x+2log5y−3log5z), using the Laws of Logarithm
2(log5x+2log5y−3log5z)=2(log5x+log5y2−log5z3)Law of Logarithm loga(AC)=ClogaA2(log5x+2log5y−3log5z)=2(log5xy2−log5z3)Law of Logarithm loga(AB)=logaA+logaB2(log5x+2log5y−3log5z)=2log5(xy2z3)Law of Logarithm loga(AB)=logaA−logaB2(log5x+2log5y−3log5z)=log5(xy2z3)2Law of Logarithm loga(AC)=ClogaA
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