Sunday, November 20, 2011

College Algebra, Chapter 2, 2.4, Section 2.4, Problem 62

Determine the area of the triangle formed by the coordinates axes and the line 2y+3x6=0

Solving for y intercept, where x=0


2y+3(0)6=02y6=02y=6y=3


The y intercept is at (0,3)

Solving for x intercept, where y=0


2(0)+3x6=03x6=03x=6x=2


The x intercept is at (2,0)

Since the y intercept is at (0,3), notice that the height of the triangle will be h=3. Consequently, if the x intercept is at (2,0), then the base of the triangle will be b=2. Thus, the area is..

A=12bh=12(2)(3)=3 square units

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