Determine the area of the triangle formed by the coordinates axes and the line 2y+3x−6=0
Solving for y intercept, where x=0
2y+3(0)−6=02y−6=02y=6y=3
The y intercept is at (0,3)
Solving for x intercept, where y=0
2(0)+3x−6=03x−6=03x=6x=2
The x intercept is at (2,0)
Since the y intercept is at (0,3), notice that the height of the triangle will be h=3. Consequently, if the x intercept is at (2,0), then the base of the triangle will be b=2. Thus, the area is..
A=12bh=12(2)(3)=3 square units
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